(2x-3)^2/3-(3x)^1/3=0

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Solution for (2x-3)^2/3-(3x)^1/3=0 equation: 


x in (-oo:+oo)

((2*x-3)^2)/3-(((3*x)^1)/3) = 0

((2*x-3)^2)/3-x = 0

((2*x-3)^2)/3+(3*(-x))/3 = 0

(2*x-3)^2+3*(-x) = 0

4*x^2-15*x+9 = 0

4*x^2-15*x+9 = 0

4*x^2-15*x+9 = 0

DELTA = (-15)^2-(4*4*9)

DELTA = 81

DELTA > 0

x = (81^(1/2)+15)/(2*4) or x = (15-81^(1/2))/(2*4)

x = 3 or x = 3/4

(x-3/4)*(x-3) = 0

((x-3/4)*(x-3))/3 = 0

((x-3/4)*(x-3))/3 = 0 // * 3

(x-3/4)*(x-3) = 0

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 3/4, 3 }

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